You can think of any molecule that has a proton on it as being an acid. They don't have to be very strong acids, but nonetheless they can behave as an acid.
If you take some arbitrary acid, H-A, and place it in a solvent usually water) it will undergo an acid base dissociation reaction as follows. An equilibrium constant Ka can be written for this equilibrium. A strong acid would have a large Ka. This indicates the proton (H+) is not tiightly bound. While a weak acid would have a very small Ka.
Now recall from general chemistry the definition of pH = -log([H+]). We define pKa the same way.
pKa = -log(Ka)
This have been done and tabulated for many thousands of compounds. Lets think about this equation for a minute. Suppose you had a very strong acid. The equilibrium above would be far to the right. The equilibrium constant would be very large and log(Ka) would be very large. However the -log(Ka) would be very small.
Chemists have done this for many compounds. Below is a small subset with which you should be familair (i.e. memorize).
Acid |
Conjugate Base |
pKa |
HI |
I- |
-10 |
H2SO4 |
HSO4- |
-9 |
HCl |
Cl- |
-4 |
RCO2H |
RCO2- |
4 to 6 |
RNH3+ |
RNH2 |
10 to 12 |
H2O |
OH- |
15.7 |
ROH |
RO- |
16 to 18 |
RC≡CH (alkyne) |
RC≡C- |
26 |
NH3 |
NH2- |
36 |
RNH2 |
RNH- |
36 |
R2C=CH2 (alkene) |
R2C=CH- |
45 |
RH (alkane) |
R- |
60 |