Resonance is a fundamental concept in understanding the stability and behavior of molecules with delocalized electrons. When a molecule has multiple valid Lewis structures, the true structure is a resonance hybrid—a blend of these resonance forms. In this section, we'll explore how to visualize and draw the resonance hybrid, focusing on key steps to represent the delocalization accurately. We will use acetic acid as an example.
Begin by drawing all significant resonance structures. Each resonance form should follow the standard rules of Lewis structures, where all atoms maintain their usual bonding preferences, and formal charges are minimized where possible.
For our acetate ion example, here are the two most significant resonance structures. This is the pattern discussed earlier, in which there is a pi bond next to an element with a full octet and lone pair electrons.
Examine the resonance forms to identify where electrons are shared among atoms. Pay particular attention to pi bonds and lone pairs on adjacent atoms, as these typically represent areas of electron delocalization.
In these two resonance structures, you can see there's a double bond (=) between the C and O atoms. In the first structure, there's a double bond between the C and top O atom, while in the second structure there's a double bond between the C and the bottom most O. Likewise, the top O on the left is negative, while the bottom O is negative on the resonance structure on the right.
Question: Draw the resonance hybrid for the following structure.
Show Answer
So there are 4 important resonance structures, as show below.
The resonance hybrid is as follows: