In alkenes, the coupling constant (J) between vinyl protons depends on their relative orientation (cis or trans). This is described by the Karplus equation, which relates the dihedral angle (θ) between protons to the coupling constant:
\[ J(\theta) = A \cos^2(\theta) + B \cos(\theta) + C \]
The larger coupling constant for trans protons arises because the spin-spin interaction is stronger when the protons are on opposite sides of the double bond.
400MHz HNMR
The structure of 1-chloro-2-methoxyethene (trans) is:
The two vinyl protons (H₁ and H₂) are in a trans configuration, so we expect a large coupling constant (J).
The coupling constant (J) is the difference between the two doublet peaks, measured in Hz. First, convert the chemical shift difference (in ppm) to Hz:
\[ \Delta \delta = 5.692 \, \text{ppm} - 5.661 \, \text{ppm} = 0.031 \, \text{ppm} \]
Convert ppm to Hz using the NMR frequency (400 MHz):
\[ J = \Delta \delta \times \text{NMR frequency} = 0.031 \, \text{ppm} \times 400 \, \text{MHz} = 12.4 \, \text{Hz} \]
Based on the coupling constant (J = 9.3 Hz), the spectrum is consistent with a cis configuration. If the compound is known to be trans, this discrepancy might require further investigation (e.g., checking sample purity or considering substituent effects).