Strategy for Balancing Chemical Reactions

Balancing chemical equations involves ensuring that the number of atoms of each element is the same on both sides of the equation. Here's a step-by-step procedure using the example:

\[ \text{NH}_3 + \text{O}_2 \rightarrow \text{N}_2 + \text{H}_2\text{O} \]

Step 1: List the number of atoms of each element on both sides.

Left Side (Reactants):

  • Nitrogen (N): 1 (from NH₃)
  • Hydrogen (H): 3 (from NH₃)
  • Oxygen (O): 2 (from O₂)

Right Side (Products):

  • Nitrogen (N): 2 (from N₂)
  • Hydrogen (H): 2 (from H₂O)
  • Oxygen (O): 1 (from H₂O)

Step 2: Identify the elements that are unbalanced.

  • Nitrogen: 1 (left) vs. 2 (right)
  • Hydrogen: 3 (left) vs. 2 (right)
  • Oxygen: 2 (left) vs. 1 (right)

Step 3: Balance the elements one at a time.

a) Balance Nitrogen (N):

There are 2 nitrogen atoms on the right (N₂), so we need 2 nitrogen atoms on the left. Adjust NH₃ to 2NH₃:

\[ 2\text{NH}_3 + \text{O}_2 \rightarrow \text{N}_2 + \text{H}_2\text{O} \]

Now:

  • Nitrogen: 2 (left) vs. 2 (right) → Balanced.

b) Balance Hydrogen (H):

There are 6 hydrogen atoms on the left (2NH₃ → 2 × 3 = 6). Adjust H₂O to 3H₂O to balance hydrogen:

\[ 2\text{NH}_3 + \text{O}_2 \rightarrow \text{N}_2 + 3\text{H}_2\text{O} \]

Now:

  • Hydrogen: 6 (left) vs. 6 (right) → Balanced.

c) Balance Oxygen (O):

There are 2 oxygen atoms on the left (O₂). There are 3 oxygen atoms on the right (3H₂O → 3 × 1 = 3). Adjust O₂ to \( \frac{3}{2} \)O₂ to balance oxygen:

\[ 2\text{NH}_3 + \frac{3}{2}\text{O}_2 \rightarrow \text{N}_2 + 3\text{H}_2\text{O} \]

Now:

  • Oxygen: 3 (left) vs. 3 (right) → Balanced.

Step 4: Eliminate fractions by multiplying the entire equation by 2:

\[ 4\text{NH}_3 + 3\text{O}_2 \rightarrow 2\text{N}_2 + 6\text{H}_2\text{O} \]

Final Balanced Equation:

\[ 4\text{NH}_3 + 3\text{O}_2 \rightarrow 2\text{N}_2 + 6\text{H}_2\text{O} \]

Verification:

Left Side:

  • Nitrogen: 4 (from 4NH₃)
  • Hydrogen: 12 (from 4NH₃)
  • Oxygen: 6 (from 3O₂)

Right Side:

  • Nitrogen: 4 (from 2N₂)
  • Hydrogen: 12 (from 6H₂O)
  • Oxygen: 6 (from 6H₂O)

The equation is now balanced!