The SN1 mechanism proceeds through two distinct steps:
In the first step, the leaving group (LG) dissociates from the substrate, forming a positively charged carbocation intermediate. This is the rate-determining step (RDS) because it is significantly slower than the subsequent step. The rate of the reaction depends *only* on the concentration of the substrate ([R-LG]), not the nucleophile, as the nucleophile is not involved in the rate-determining step.
Rate = -k[R-LG]
Question: Can you solve this by using separation of variables and then integrating from the initial concentration [R-LG]o at t=0 to some arbitrary [R-LG] at t=t?
Show AnswerCarbocation stability is a crucial factor in SN1 reactions. The order of carbocation stability is tertiary (3°) > secondary (2°) > primary (1°) > methyl. This stability trend is due to the electron-donating inductive effects of alkyl groups and hyperconjugation, which delocalize the positive charge and stabilize the carbocation.
For example, if tert-butyl chloride is placed in water, it will undergo loss of a leaving group to form a stable 3° carbocation:
The nucleophile rapidly attacks the planar carbocation intermediate. Because the carbocation is planar, the nucleophile can attack from either side with equal probability. If the starting material is chiral, this leads to racemization (formation of a racemic mixture or a mixture of enantiomers if the carbocation is not symmetrical).
In the tert-butyl chloride example, a water molecule (the nucleophile) attacks the carbocation. This initially forms an oxonium ion, which is then rapidly deprotonated to yield the final product, tert-butyl alcohol: