Quantitative Chemical Analysis

✏️ Two-Part Practice: Acid Analysis
Scenario: You are analyzing a 10.0 mL sample of an unknown acid ($H^+$) using a 0.100 M NaOH solution as your titrant. Part A: Finding Moles of Titrant
The titration takes 15.5 mL of NaOH to reach the color change (endpoint). How many moles of NaOH were used? Click for Part A Answer

Moles = Molarity × Volume (L)
0.100 mol/L × 0.0155 L = 0.00155 moles NaOH

Part B: Calculating Unknown Molarity
Based on the 1:1 reaction ratio, there must also be 0.00155 moles of acid in the original 10.0 mL sample. What is the Molarity of the acid? Click for Part B Answer

Molarity = moles / Liters
0.00155 mol / 0.010 L = 0.155 M Acid