Thermochemistry is the study of heat absorbed or released during chemical and physical changes. In health sciences, this is the basis for understanding metabolism—how your body converts food (potential energy) into heat and work (kinetic energy).
In a clinical setting, knowing the direction of heat flow is vital for patient care (e.g., using heat lamps vs. cold packs):
To calculate how much energy a substance absorbs, we must distinguish between these two related properties:
Imagine you have two cast iron pans. A small pan (808 g) and a large pan (4040 g). The specific heat of iron is 0.449 J/g°C.
Step 1 (Part A): Calculating Specific Heat vs. Heat Capacity
If it takes 18,140 J to raise the temperature of the small pan by 50.0 °C, what is the Specific Heat (c) of the iron?
Hint: c = q / (mΔT)
c = 18,140 J / (808 g × 50.0 °C) = 0.449 J/g°C
Step 2 (Part B): Applying the Concept of Mass
Using the Specific Heat found in Part A, how much heat (q) is required to raise the large pan (4040 g) by that same 50.0 °C?
Question: Since the mass is 5x larger, will the heat required be more or less?
q = c × m × ΔT
q = 0.449 J/g°C × 4040 g × 50.0 °C = 90,700 J
Logic: Because the specific heat is an intensive property, it stays the same, but the total heat capacity of the large pan is 5x higher!
Water has a very high specific heat (4.184 J/g°C), which allows the human body to maintain a stable internal temperature.
Step 1 (Part A): Calculating ΔT
A flask containing 800 g of water is heated from 21 °C to 85 °C. What is the temperature change (ΔT)?
ΔT = Tfinal - Tinitial = 85 °C - 21 °C = 64 °C
Step 2 (Part B): Determining Total Heat Absorbed
Using your answer from Part A, calculate the total heat (q) in Joules absorbed by the water.
Formula: q = c × m × ΔT
q = 4.184 J/g°C × 800 g × 64 °C = 214,221 J (or 2.1 × 105 J)