Thermochemistry Basics

5.1 Thermochemistry: Energy, Heat, and Temperature

Background: Understanding Energy Flow

Thermochemistry is the study of heat absorbed or released during chemical and physical changes. In health sciences, this is the basis for understanding metabolism—how your body converts food (potential energy) into heat and work (kinetic energy).

  • Thermal Energy: Kinetic energy associated with the random motion of atoms and molecules.
  • Temperature: A quantitative measure of "hot" or "cold." It reflects the average kinetic energy of the particles.
  • Heat (q): The transfer of thermal energy between two bodies at different temperatures. Heat always flows spontaneously from a higher-temperature object to a lower-temperature object until thermal equilibrium is reached.

Distinguishing Processes: Exothermic vs. Endothermic

In a clinical setting, knowing the direction of heat flow is vital for patient care (e.g., using heat lamps vs. cold packs):

  • Exothermic Process: A change that releases heat to the surroundings (e.g., a hand warmer or combustion).
  • Endothermic Process: A change that absorbs heat from the surroundings (e.g., a chemical cold pack used for sports injuries).

Background: Heat Capacity vs. Specific Heat

To calculate how much energy a substance absorbs, we must distinguish between these two related properties:

  • Heat Capacity (C): An extensive property (depends on amount). It is the heat required to raise the temperature of an entire object by 1°C. (Example: A large iron pot has a higher heat capacity than a small iron nail).
  • Specific Heat (c): An intensive property (depends only on the material). It is the heat required to raise exactly 1 gram of a substance by 1°C.

✏️ Integrated Practice: The "Iron Frying Pan" Challenge

Imagine you have two cast iron pans. A small pan (808 g) and a large pan (4040 g). The specific heat of iron is 0.449 J/g°C.

Step 1 (Part A): Calculating Specific Heat vs. Heat Capacity
If it takes 18,140 J to raise the temperature of the small pan by 50.0 °C, what is the Specific Heat (c) of the iron?
Hint: c = q / (mΔT)

Click for Part A Answer

c = 18,140 J / (808 g × 50.0 °C) = 0.449 J/g°C

Step 2 (Part B): Applying the Concept of Mass
Using the Specific Heat found in Part A, how much heat (q) is required to raise the large pan (4040 g) by that same 50.0 °C?
Question: Since the mass is 5x larger, will the heat required be more or less?

Click for Part B Answer

q = c × m × ΔT
q = 0.449 J/g°C × 4040 g × 50.0 °C = 90,700 J
Logic: Because the specific heat is an intensive property, it stays the same, but the total heat capacity of the large pan is 5x higher!

✏️ Integrated Practice: Measuring Heat in Water

Water has a very high specific heat (4.184 J/g°C), which allows the human body to maintain a stable internal temperature.

Step 1 (Part A): Calculating ΔT
A flask containing 800 g of water is heated from 21 °C to 85 °C. What is the temperature change (ΔT)?

Click for Part A Answer

ΔT = Tfinal - Tinitial = 85 °C - 21 °C = 64 °C

Step 2 (Part B): Determining Total Heat Absorbed
Using your answer from Part A, calculate the total heat (q) in Joules absorbed by the water.
Formula: q = c × m × ΔT

Click for Part B Answer

q = 4.184 J/g°C × 800 g × 64 °C = 214,221 J (or 2.1 × 105 J)